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How do I do top 1 in Oracle? How do I do the following? Can you tell us the order according to which you want 'top 1'? First of all you should never ever rely on the DB engine to do that, ever.
If you want to know things like that, put in a sequencer. When you do that it is guaranteed that they will be numbered in the order they were inserted.
Very usful material on this topic use-the-index-luke. If you want just a first selected row, you can: Not sure what the second example is supposed to achieve This is good if you only want 1 row and don't care which.
If you want specific rows, like the most recent record, you need to do the sort in a subselect, like Vash's answer.
Oracle assigns rownums before the sort. And Patrick, good point I think the syntax is incorrect on that. The difference between the first and second example is that the first one selects A row any row, with no order.
The second example gets the value of the first row, without doing an order inner query as per examples below. The syntax in not correct in: I stand corrected see below.
Will switch votes once time is up. This for sure must be the winning answer in this thread. MSK 4 You are right RafaelMerlin.
It would be useful when retrieving data between top X and top Y. One problem with this solution and with max field variant too that you cannot do things like "select Dec 9 '15 at 8: In such case we can use CTE as in the outer part.